Calculations:
1. Find the speed as the block slides through the photogate.
velocity=(delta)x/(delta)t
V= 0.076 meters/0.066 seconds
V= 1.15 meters/second
2. Concider the previous speed you found as the initial speed of the sliding block. Use Vi and the distance it slid to find the acceleration of the block.
V(final)^2= V(inital)^2 + 2a(distance)
0= 1.15 + 2a(.225 m)
0= 1.3225 + .506a
-1.3225=.506a
-2.61 m/s/s = a
3. Using the previous acceleration, find the net force acting on the sliding black. This will be our frictional force.
F(net)=ma
F(f)=ma
F(f)=(.131 kg)(-2.61 m/s/s)
F(f)= -.0342 N
4. Useing our frictional force and normal force, find the coefficient of kinetic friction between the two surfaces.
Fw=Wt=ma
(.131 kg)(9.8m/s/s)= -1.28 N
Mm= Frictional Force/Net Froce
Kinetic Force= -.342 N/-1.28 =
0.267
Questions:
1. With your second trial, how did the force from friction change compared to the first trial?
In the second trial, the frictional force was less than the first trial.
2. With your second trial, how did the coefficient of friction change compared to the first trial?
The coefficient in the second trial was a little less because the frictional force was slightly less while the normal force remained the same. Overall, they were very similar.
3. Name at least two sources of experimental error that may have affected your results.
The first thing that could have increased experimental error is that the block was not always pushed without rotating. A slight spin on the block would have affected the distance and speed results of the trial. Another possible source of error is that the block did not always in a straight line through the gate. This made it impossible to get exact measurements of distance traveled beyond the gate, which would have skewed our data.
4. As the block is sliding to a halt, draw and label all the force vectors acting on the block:
5. If instead, the block was coated with a rubber surface, how do you think your μ value would change?
If the block had been coated in rubber the μ value would have increased because rubber would create more friction than the polished wood of the block. This would result in a greater friction force, which would in turn raise the value of μ.
1. Find the speed as the block slides through the photogate.
velocity=(delta)x/(delta)t
V= 0.076 meters/0.066 seconds
V= 1.15 meters/second
2. Concider the previous speed you found as the initial speed of the sliding block. Use Vi and the distance it slid to find the acceleration of the block.
V(final)^2= V(inital)^2 + 2a(distance)
0= 1.15 + 2a(.225 m)
0= 1.3225 + .506a
-1.3225=.506a
-2.61 m/s/s = a
3. Using the previous acceleration, find the net force acting on the sliding black. This will be our frictional force.
F(net)=ma
F(f)=ma
F(f)=(.131 kg)(-2.61 m/s/s)
F(f)= -.0342 N
4. Useing our frictional force and normal force, find the coefficient of kinetic friction between the two surfaces.
Fw=Wt=ma
(.131 kg)(9.8m/s/s)= -1.28 N
Mm= Frictional Force/Net Froce
Kinetic Force= -.342 N/-1.28 =
0.267
Questions:
1. With your second trial, how did the force from friction change compared to the first trial?
In the second trial, the frictional force was less than the first trial.
2. With your second trial, how did the coefficient of friction change compared to the first trial?
The coefficient in the second trial was a little less because the frictional force was slightly less while the normal force remained the same. Overall, they were very similar.
3. Name at least two sources of experimental error that may have affected your results.
The first thing that could have increased experimental error is that the block was not always pushed without rotating. A slight spin on the block would have affected the distance and speed results of the trial. Another possible source of error is that the block did not always in a straight line through the gate. This made it impossible to get exact measurements of distance traveled beyond the gate, which would have skewed our data.
4. As the block is sliding to a halt, draw and label all the force vectors acting on the block:
5. If instead, the block was coated with a rubber surface, how do you think your μ value would change?
If the block had been coated in rubber the μ value would have increased because rubber would create more friction than the polished wood of the block. This would result in a greater friction force, which would in turn raise the value of μ.
I like the block picture........well done!
20/20